Difference between revisions of "Unallocated Memory Reference"

Latest revision as of 13:59, 14 April 2014

include<stdio.h>

int main() {

int *a;
*a=5;
printf("%d",a);

return 0;

}

</syntaxhighlight>

Solution by Arjun Suresh

<syntaxhighlight lang="c"> int *a; </syntaxhighlight> This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int

a = 5;

</syntaxhighlight> This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault

@@ Line 12: / Line 12: @@
 </syntaxhighlight>
- Invalid memory access
+==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
+<syntaxhighlight lang="c">
+int *a;
+</syntaxhighlight>
+This declares a as an integer pointer, meaning 'a' can point to any memory address which contains an int
+<syntaxhighlight lang="c">
+*a = 5;
+</syntaxhighlight>
+This makes the content of the address pointed to by 'a' 5. But 'a' is not pointing to any valid address (int *a assigns garbage value to 'a') and hence this assignment can cause segmentation fault
+{{Template:FBD}}
-int *a; // This declares a as an integer pointer, meaning a can point to a memory address which contains an int
-*a = 5; //Makes the content of the address pointed to by a 5. But a is not pointing to any valid address (int *a assigns garbage value to a) and hence this assignment can cause segmentation fault
-<disqus/>
 [[Category:Coding Questions]]