GATE2006 q1 - Revision history

Arjun Suresh at 11:47, 15 July 2014

2014-07-15T11:47:55Z

2014-07-10T15:42:06Z

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2014-04-15T07:09:53Z

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← Older revision		Revision as of 11:47, 15 July 2014
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	[[Category: GATE2006]]		[[Category: GATE2006]]
−	[[Category: Mathematics questions]]	+	[[Category: Mathematics questions from GATE]]

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-[[Category: Mathematics]]
 [[Category: GATE2006]]
 [[Category: Mathematics questions]]

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 Consider the polynomial $p(x) = a_0 + a_1x + a_2x^2 + a_3x^3$ , where $a_i &ne;0\; &forall;i$. The minimum number of
-multiplications needed to evaluate p on an input x is:
+multiplications needed to evaluate $p$ on an input $x$ is:
 	<b>(A) </b>3
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-		As we can see, here we need only 3 multiplications, so option <b>(A)</b> is correct.
+		As we can see, here we need only three multiplications, so option <b>(A)</b> is correct.
-		Note that in question paper, $a_3x^2$ is written instead of $a_3x^3$, but for $a_3x^2$, answer is 2, because we can save
+		Note that in question paper, $a_3x^2$ is written instead of $a_3x^3$, but for $a_3x^2$, answer is $2$, because we can save
-		one more multiplication between $a_3$ and x, but 2 is not in the options, so I guess question paper had a printing mistake.
+		one more multiplication between $a_3$ and $x$, but $2$ is not in the options, so I guess question paper had a printing mistake.

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 [[Category: Mathematics]]
 [[Category: GATE2006]]
-[[Category: Previous year GATE questions]]
+[[Category: Mathematics questions]]

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 ==={{Template:Author|Happy Mittal|{{mittalweb}} }}===
 	 We can use just horner's method, according to which, we can write p(x) as :
-<center>
-		$p(x) = a_0 + x(a_1 + x(a_2 + a_3x))$ </center>
+		$$p(x) = a_0 + x(a_1 + x(a_2 + a_3x))$$