GATE2010 q26 - Revision history

Arjun Suresh at 11:53, 15 July 2014

2014-07-15T11:53:06Z

2014-07-14T12:04:27Z

2014-07-13T22:59:39Z

2014-07-13T22:59:09Z

2014-06-29T14:40:03Z

2014-06-29T14:27:30Z

2014-06-29T12:16:41Z

2014-04-15T17:24:38Z

2014-04-15T07:12:07Z

2014-04-14T22:09:15Z

← Older revision		Revision as of 11:53, 15 July 2014
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	[[Category: GATE2010]]		[[Category: GATE2010]]
−	[[Category: Probability questions]]	+	[[Category: Probability questions from GATE]]

@@ Line 1: / Line 1: @@
-Consider a company that assembles computers. The probability of a faulty
+Consider a company that assembles computers. The probability of a faulty assembly of any computer is $p$. The company therefore subjects each computer to a testing process. This testing process gives the correct result for any computer with a probability of $q$. What is the probability of a computer being declared faulty?
-		'''(A) $pq + (1 - p)(1 - q)$'''
+'''(A) $pq + (1 - p)(1 - q)$'''
-		(B) $(1 - q)p$
+(B) $(1 - q)p$
-		(C) $(1 - q)p$
+(C) $(1 - q)p$
-		(D) $pq$
+(D) $pq$
 ==={{Template:Author|Happy Mittal|{{mittalweb}} }}===

← Older revision		Revision as of 22:59, 13 July 2014
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	[[Category: GATE2010]]		[[Category: GATE2010]]
	[[Category: Probability questions]]		[[Category: Probability questions]]
−	~~[[Category:Mathematics questions ]]~~

@@ Line 21: / Line 21: @@
 {{Template:FBD}}
-[[Category:Probability and Combinatorics]]
 [[Category: GATE2010]]
 [[Category: Probability questions]]
 [[Category:Mathematics questions ]]

@@ Line 1: / Line 1: @@
 Consider a company that assembles computers. The probability of a faulty
-		assembly of any computer is p. The company therefore subjects each
+		assembly of any computer is $p$. The company therefore subjects each
 		computer to a testing process. This testing process gives the correct result for
-		any computer with a probability of q. What is the probability of a computer
+		any computer with a probability of $q$. What is the probability of a computer
 		being declared faulty?
-		'''(A) pq + (1 - p)(1 - q)'''
+		'''(A) $pq + (1 - p)(1 - q)$'''
-		(B) (1 - q)p
+		(B) $(1 - q)p$
-		(C) (1 - q)p
+		(C) $(1 - q)p$
-		(D) pq
+		(D) $pq$
 ==={{Template:Author|Happy Mittal|{{mittalweb}} }}===
   P(declared faulty)
   = P(actually faulty)*P(declared faulty|actually faulty) +  P(not faulty)*P(declared faulty|not faulty)
-  = p*q + (1-p)*(1-q)
+  = $p*q + (1-p)*(1-q)$
 		So, option <b>(A)</b> is correct.
@@ Line 24: / Line 24: @@
 [[Category: GATE2010]]
 [[Category: Probability questions]]
-[[Category:Mathematics Questions ]]
+[[Category:Mathematics questions ]]

← Older revision		Revision as of 12:16, 29 June 2014
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	[[Category: GATE2010]]		[[Category: GATE2010]]
	[[Category: Probability questions]]		[[Category: Probability questions]]
		+	[[Category:Mathematics Questions from GATE]]

@@ Line 23: / Line 23: @@
 [[Category:Probability and Combinatorics]]
 [[Category: GATE2010]]
-[[Category: Previous year GATE questions]]
+[[Category: Mathematics questions]]