GATE2013 q2 - Revision history

Arjun Suresh at 11:53, 15 July 2014

2014-07-15T11:53:38Z

2014-07-14T11:54:46Z

2014-06-29T21:21:27Z

2014-04-15T17:26:40Z

2014-04-15T07:16:06Z

2014-04-14T13:59:07Z

2014-01-06T12:56:01Z

2013-12-11T10:51:35Z

2013-12-10T16:40:05Z

2013-12-10T16:23:58Z

← Older revision		Revision as of 11:53, 15 July 2014
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	[[Category: GATE2013]]		[[Category: GATE2013]]
−	[[Category: Probability questions]]	+	[[Category: Probability questions from GATE]]

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-Suppose <math>p</math> is the number of cars per minute passing through a certain road junction between 5 PM and 6 PM, and <math>p</math> has a Poisson distribution with mean 3. What is the probability of observing fewer than 3 cars during any given minute in this interval?
+Suppose <math>p</math> is the number of cars per minute passing through a certain road junction between 5 PM and 6 PM, and <math>p</math> has a Poisson distribution with mean $3$. What is the probability of observing fewer than 3 cars during any given minute in this interval?
 (A) $8/(2e^{3})$
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 Poisson Probability Density Function (with mean $\lambda$) = $\lambda^{k} / (e^{\lambda}k!)$,
-We have to sum the probability density function for k = 0,1 and 2 and $\lambda$ = 3 (thus finding the cumulative mass function)
+We have to sum the probability density function for $k = 0,1$ and $2$ and $\lambda$ = 3 (thus finding the cumulative mass function)
 =$(1/e^3) + (3/e^3) + (9/2e^3)$
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 [[Category: Probability and Combinatorics]]
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 [[Category: Probability and Combinatorics]]
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 [[Category: Probability and Combinatorics]]
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 (D) $26/(2e^{3})$
-===Solution===
+==={{Template:Author|Arjun Suresh|{{arjunweb}} }}===
 Poisson Probability Density Function (with mean $\lambda$) = $\lambda^{k} / (e^{\lambda}k!)$,

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