Arjun Suresh (talk | contribs) (Created page with "Consider a company that assembles computers. The probability of a faulty assembly of any computer is p. The company therefore subjects each computer to a testing process. ...") |
Arjun Suresh (talk | contribs) |
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(B) (1 - q)p | (B) (1 - q)p | ||
| − | (C) | + | (C) (1 - q)p |
(D) pq | (D) pq | ||
==={{Template:Author|Happy Mittal|{{mittalweb}} }}=== | ==={{Template:Author|Happy Mittal|{{mittalweb}} }}=== | ||
| − | P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) + | + | P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) + |
P(not faulty)*P(declared faulty|not faulty) = p*q + (1-p)*(1-q). | P(not faulty)*P(declared faulty|not faulty) = p*q + (1-p)*(1-q). | ||
| − | + | ||
| − | So option <b>(A)</b> is correct. | + | So, option <b>(A)</b> is correct. |
{{Template:FBD}} | {{Template:FBD}} | ||
Consider a company that assembles computers. The probability of a faulty assembly of any computer is p. The company therefore subjects each computer to a testing process. This testing process gives the correct result for any computer with a probability of q. What is the probability of a computer being declared faulty?
(A) pq + (1 - p)(1 - q)
(B) (1 - q)p
(C) (1 - q)p
(D) pq
P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) +
P(not faulty)*P(declared faulty|not faulty) = p*q + (1-p)*(1-q).
So, option (A) is correct.
Consider a company that assembles computers. The probability of a faulty assembly of any computer is p. The company therefore subjects each computer to a testing process. This testing process gives the correct result for any computer with a probability of q. What is the probability of a computer being declared faulty?
(A) pq + (1 - p)(1 - q)
(B) (1 - q)p
(C) (1 - q)p
(D) pq
P(declared faulty) = P(actually faulty)*P(declared faulty|actually faulty) +
P(not faulty)*P(declared faulty|not faulty) = p*q + (1-p)*(1-q).
So, option (A) is correct.
GATECSE